GATE_AE_2027_MOCK_04_Q61 GATE 2027 Aerospace Engineering All-India Master Mock 04 (Aerospace Structures, Thin-Walled Beams & Aeroelasticity) NAT · 2 Marks
Aerospace Structures • Thin-Walled Structures • Bredt-Batho Torsion & Shear Center

A closed thin-walled tube of uniform thickness t = 2 mm has an enclosed cross-sectional area A_m = 0.25 m^2. The maximum allowable shear stress in the material is au_{allow} = 80 MPa. What is the maximum torque T_{max} in kilonewtons-meter (kN*m) that can be applied to the tube?

Answer Key:
80

Step-by-Step Verified Solution

### Solution: Allowable shear flow q_{allow} = au_{allow} * t = 80 * 10^6 Pa * 0.002 m = 160000 N/m. Bredt-Batho formula: T = 2 * A_m * q = 2 * 0.25 m^2 * 160000 N/m = 80000 N*m = 80 kN*m. Correct: 80.
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