GATE_AE_2027_MOCK_04_Q60
GATE 2027 Aerospace Engineering All-India Master Mock 04 (Aerospace Structures, Thin-Walled Beams & Aeroelasticity)
NAT · 2 Marks
Aerospace Structures • Strength of Materials & Elasticity • Euler Buckling of Columns & Energy Methods
A uniform column of length L = 1.5 m with bending stiffness EI = 2500 N*m^2 is pinned at one end and fixed at the other (effective length factor K ≈ 0.70). What is the Euler critical buckling load P_{cr} in kilonewtons (kN)? (Take \pi^2 ≈ 9.8696, round to two decimal places).
Answer Key:
22.38
Step-by-Step Verified Solution
### Solution: Effective length L_e = 0.70 * 1.5 = 1.05 m. P_{cr} = \pi^2 EI / L_e^2 = 9.8696 * 2500 / (1.05)^2 = 24674 / 1.1025 ≈ 22380 N ≈ 22.38 kN. Correct: 22.38 (range 22.10 to 22.60).