For an isotropic linear elastic material with Young's modulus $E$ and Poisson's ratio $\nu$, the shear modulus $G$ is given by:

(A) G = \frac{E}{2(1 + \nu)}

(B) G = \frac{E}{3(1 - 2\nu)}

(C) G = \frac{E}{1 + \nu}

(D) G = \frac{2E}{1 - \nu}

Answer Key:

A

### Solution: The isotropic elasticity relation between $E$, $G$, and $\nu$ is $E = 2G(1 + \nu) \implies G = \frac{E}{2(1 + \nu)}$. Correct: A.

← Prev Question Next Question →