GATE_AE_2027_MOCK_01_Q30 GATE 2027 Aerospace Engineering All-India Master Mock 01 (Foundation & Standard Core Calibration) NAT · 1 Mark
Propulsion • Rocket Propulsion • Tsiolkovsky Rocket Equation & Specific Impulse

A liquid rocket engine produces a thrust of $F = 44145\text{ N}$ while consuming propellant at a rate of $\dot{m} = 15\text{ kg/s}$. Taking standard gravity $g_0 = 9.81\text{ m/s}^2$, what is the specific impulse $I_{sp}$ of the engine in seconds?

Answer Key:
300

Step-by-Step Verified Solution

### Solution: Specific impulse: $I_{sp} = \frac{F}{\dot{m} g_0} = \frac{44145}{15 \times 9.81} = \frac{44145}{147.15} = 300\text{ seconds}$. Correct: 300.
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