A circular thin-walled tube of mean radius R = 100 mm and wall thickness t = 2 mm is subjected to torque T = 12566 N*m. What is the shear stress au in the wall in MPa? (Take pi ≈ 3.1416, round to nearest integer).

Answer Key:

100

### Solution: Enclosed area A_m = pi * R^2 = 3.1416 * (0.1)^2 = 0.031416 m^2. Shear flow q = T / (2 A_m) = 12566 / (2 * 0.031416) = 12566 / 0.062832 = 200000 N/m. Shear stress au = q / t = 200000 N/m / 0.002 m = 100 imes 10^6 Pa = 100 MPa. Correct: 100.

← Prev Question Next Question →