GATE_AE_2027_MOCK_04_Q53 GATE 2027 Aerospace Engineering All-India Master Mock 04 (Aerospace Structures, Thin-Walled Beams & Aeroelasticity) NAT · 2 Marks
Propulsion • Thermodynamic Cycles of Gas Turbines • Brayton Cycle & Component Efficiencies

In an ideal Brayton cycle, air enters the compressor at T_1 = 300 K with pressure ratio r_p = 10. Taking \gamma = 1.4, what is the compressor exit temperature T_2 in Kelvin? (10^{0.2857} ≈ 1.9307, round off to one decimal place).

Answer Key:
579.2

Step-by-Step Verified Solution

### Solution: T_2 = T_1 * (r_p)^{(\gamma - 1)/\gamma} = 300 * 10^{(0.4/1.4)} = 300 * 1.9307 = 579.21 K ≈ 579.2 K. Correct: 579.2 (range 578.0 to 581.0).
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