GATE_AE_2027_MOCK_04_Q32 GATE 2027 Aerospace Engineering All-India Master Mock 04 (Aerospace Structures, Thin-Walled Beams & Aeroelasticity) NAT · 1 Mark
Aerospace Structures • Strength of Materials & Elasticity • Torsion of Circular Shafts

A solid circular aircraft torque shaft of radius r = 20 mm is subjected to torque T = 500 N*m. What is the polar moment of inertia J (in mm^4) of the shaft? (Take pi ≈ 3.1416, round to nearest integer).

Answer Key:
251327

Step-by-Step Verified Solution

### Solution: J = (pi / 2) * r^4 = (3.1416 / 2) * (20)^4 = 1.5708 * 160000 = 251327 mm^4. Correct: 251327 (range 251000 to 252000).
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