GATE_AE_2027_MOCK_04_Q22
GATE 2027 Aerospace Engineering All-India Master Mock 04 (Aerospace Structures, Thin-Walled Beams & Aeroelasticity)
NAT · 1 Mark
Flight Mechanics & Space Dynamics • Atmospheric Flight Mechanics • Stalling Speed & Maximum Lift Coefficient
An aircraft of mass m = 4000 kg has wing area S = 20 m^2 and C_{L,max} = 1.60. Taking sea-level air density ho = 1.225 kg/m^3 and g = 9.81 m/s^2, what is the stall speed V_{stall} in m/s? (Round to one decimal place).
Answer Key:
44.8
Step-by-Step Verified Solution
### Solution: W = 4000 * 9.81 = 39240 N. V_{stall} = sqrt(2 * W / ( ho * S * C_{L,max})) = sqrt(2 * 39240 / (1.225 * 20 * 1.6)) = sqrt(78480 / 39.2) = sqrt(2002.04) ≈ 44.74 ≈ 44.8 m/s. Correct: 44.8 (range 44.5 to 45.1).