GATE_AE_2027_MOCK_03_Q07 GATE 2027 Aerospace Engineering All-India Master Mock 03 (Flight Dynamics, Controls & Space Trajectories) NAT · 2 Marks
General Aptitude • Quantitative Aptitude • Data Interpretation & Statistics

The marks scored by 6 flight mechanics students in an exam are: 48, 56, 62, 70, 78, 86. What is the mean score?

Answer Key:
66.67

Step-by-Step Verified Solution

### Solution: Mean = (48 + 56 + 62 + 70 + 78 + 86) / 6 = 400 / 6 = 66.6667... ≈ 66.67. Correct: 66.67 (range 66.50 to 66.80).
← Prev Question Next Question →
Solve in CBT Simulator