A fighter aircraft performs a coordinated level turn at true airspeed $V = 240\text{ m/s}$ with a bank angle $\phi = 60^\circ$. What is the radius of the turn $R$ in meters? (Take $g = 9.81\text{ m/s}^2$, round off to nearest integer).

Answer Key:

3391

### Solution: In a coordinated level turn, $R = \frac{V^2}{g \tan\phi}$. For $\phi = 60^\circ$, $\tan 60^\circ = \sqrt{3} \approx 1.73205$. $R = \frac{(240)^2}{9.81 \times 1.73205} = \frac{57600}{16.9914} \approx 3390.5 \approx 3391\text{ m}$. Correct: 3391 (range 3370 to 3410).

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