GATE AE 2026 • Q42 MCQ • 2 Marks

Aerodynamics & Fluid Mechanics

Compressible Flow & Shocks

Subtopic: Normal & Oblique Shock Waves

Question Statement:

The figure below shows a compressor stage with station numbers 1, 2, and 3 as indicated. If p0i, T0i, and Ci refer to the average values of total pressure, total temperature, and absolute flow speed, respectively, at the ith station, select the CORRECT option considering losses.

Options:

  • (A) p01 < p02, p02 > p03 ; T01 < T02, T02 ≈ T03 ; C1 < C2, C2 > C3
  • (B) p01 < p02, p02 = p03 ; T01 < T02, T02 ≈ T03 ; C1 < C2, C2 = C3
  • (C) p01 < p02, p02 > p03 ; T01 < T02, T02 < T03 ; C1 > C2, C2 > C3
  • (D) p01 < p02, p02 < p03 ; T01 < T02, T02 < T03 ; C1 = C2 = C3

Official Answer Key:

A

Step-by-Step Solution & Explanation

### **Detailed Step-by-Step Solution (GATE AE 2026 Q.42)** **1. Intuitive Physical Setup & Given Parameters**: The problem depicts a single stage of an axial compressor: - Station 1: Rotor inlet - Station 2: Rotor exit / Stator inlet - Station 3: Stator exit We are given total pressure $p_{0i}$, total temperature $T_{0i}$, and absolute flow speed $C_i$ at each station, and asked to identify the correct inequalities considering real losses. **2. Step-by-Step Turbomachinery Aerodynamic Derivation**: 1. **Total Pressure ($p_{0i}$) Behavior**: - In the **rotor** ($1 \to 2$), mechanical work is input into the air stream via rotating blades. The total pressure rises significantly: $p_{02} > p_{01}$ - In the **stator** ($2 \to 3$), the blades are stationary (no work transfer, $\dot{W} = 0$). Fluid flows through diffusing passages where boundary layer friction and turbulence cause unavoidable stagnation pressure loss: $p_{03} < p_{02} \implies p_{02} > p_{03}$ 2. **Total Temperature ($T_{0i}$) Behavior**: - In the **rotor** ($1 \to 2$), work addition increases the stagnation enthalpy and total temperature: $T_{02} > T_{01}$ - In the **stator** ($2 \to 3$), since no shaft work is added or extracted and heat transfer through the casing is negligible (adiabatic stationary vane): $h_{03} = h_{02} \implies T_{02} \approx T_{03}$ 3. **Absolute Velocity ($C_i$) Behavior**: - The rotor accelerates absolute flow in the tangential direction while diffusing relative velocity, resulting in a net increase in absolute velocity: $C_2 > C_1 \implies C_1 < C_2$ - The stator converts dynamic pressure (kinetic energy) into static pressure by decelerating the absolute flow: $C_3 < C_2 \implies C_2 > C_3$ 4. Combining all three criteria: $p_{01} < p_{02}, \quad p_{02} > p_{03}; \quad T_{01} < T_{02}, \quad T_{02} \approx T_{03}; \quad C_1 < C_2, \quad C_2 > C_3$ **3. Comprehensive Options & Distractor Analysis**: - **(A)**: ✅ **CORRECT**. Accurately satisfies rotor work input ($p_{01}<p_{02}, T_{01}<T_{02}$), stator friction loss ($p_{03}<p_{02}$), stator adiabatic conservation ($T_{02}\approx T_{03}$), and stator diffusion ($C_3<C_2$). - **(B)**: ❌ **INCORRECT**. Claims $p_{02} = p_{03}$, which ignores stator frictional losses. - **(C)**: ❌ **INCORRECT**. Claims $T_{02} < T_{03}$, implying work addition in the stationary stator. - **(D)**: ❌ **INCORRECT**. Claims $p_{02} < p_{03}$, which violates second law of thermodynamics in a stationary duct. **4. Official Master Key & Exam Takeaway**: - **Official Answer Key**: **A** - **Exam Takeaway**: Rotors add shaft work ($p_0 \uparrow, T_0 \uparrow$); stators only diffuse flow without work ($T_0 = \text{const}$, $p_0 \downarrow$ due to entropy generation).

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